Two Crystal Balls O(Math.sqrt(n))

Given 2 crystal balls that will break if dropped from a high enough distance, determine the exact spot in which they’ll break in the most optimized way.

Solution:

function two_crystal_balls(breaks) {
  const jmpAmount = Math.floor(Math.sqrt(breaks.length));

  let i = jmpAmount;
  for (; i < breaks.length; i += jmpAmount) {
    if (breaks[i]) {
      break;
    }
  }
  console.log(i, "i");

  i -= jmpAmount;
  console.log(i, "i");

  for (let j = i; j < breaks.length; j++) {
    if (breaks[j]) {
      console.log(j, "i");
      return j;
    }
  }
  return -1;
}

console.log(two_crystal_balls([false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, false, true, true, true, true, true, true, true, true, true, true, true]))